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49x^2/64x-36=0
Domain of the equation: 64x!=0We multiply all the terms by the denominator
x!=0/64
x!=0
x∈R
49x^2-36*64x=0
Wy multiply elements
49x^2-2304x=0
a = 49; b = -2304; c = 0;
Δ = b2-4ac
Δ = -23042-4·49·0
Δ = 5308416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5308416}=2304$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2304)-2304}{2*49}=\frac{0}{98} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2304)+2304}{2*49}=\frac{4608}{98} =47+1/49 $
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